how do i find the second derivative of xsinx?

Question

how do i find  the second derivative of  xsinx?

anonymous · Answer

you have to find first derivative first

anonymous · Answer

that is a good first step, yes

anonymous · Answer

for the first derivative i got xcosx+sinx

anonymous · Answer

yes that is it.  now you have to use the product rule again on the first part

anonymous · Answer

ok so then i got x(-sinx)+cosx+sinx now what?

anonymous · Answer

a mistake here

anonymous · Answer

you got the derivative of the first part correct but you forgot to take the derivative of sin(x)

anonymous · Answer

should get 
$$-x\sin(x)+\cos(x)+\cos(x)$$

anonymous · Answer

oh so x(-sinx)+2cosx? since sinx cosx and u add them?

anonymous · Answer

yes you will probably see it written as 
$$2\cos(x)-x\sin(x)$$

anonymous · Answer

oh so x(-sinx)+2cosx? since sinx cosx and u add them?

anonymous · Answer

oh got it ,does it matter the order in which u put cos and sin?

anonymous · Answer

nope, one of those property whose name I can't recall

anonymous · Answer

k thanks