Question

find the absolute max and min values of f(x) in the given interval: f(x)= x^2-2x+10 on -1\[-1 \le x \le2\]

Answer 1

this is a parabola that faces up, so minimum at the vertex which is at
\[x=-\frac{b}{2a}=-\frac{-2}{2}=1\]

Answer 2

\[f(1)=9\] so that is the minimum value. to find the maximum check the endpoints and see which is biggest

Answer 3

\[logx-\log1/x \div logx^4\]