Question

How many years will it take for an initial investment of $10,000 to grow to $25,000? Assume a rate of interest of 6% compounded continuously.

Answer 1

25000=10000e^(0.06t)

Answer 2

but how do you solve for t?

Answer 3

you can do it y using log on both sides

Answer 4

so \[t = \ln (25000)\div \left[ \ln (10000) \times(.06) \right]\]?

Answer 5

ys