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Use logarithmic differentiation to calculate the derivative... e^2x multiplied by sqrt(1+x^2) divided by tan(x)^2
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\[2x+\log(\sqrt{1+x^2}))-2logtanx\]\[\frac{dy}{dx}=2+\frac{1}{\sqrt{1+x^2}}(2x)-2(\frac{1}{tanx})(\sec^2x)\]
That's the answer i got but according to my teacher the \[2+ x \div 1+x ^{2}- 4\csc2x\]
and thats multiplied by the original equation
i think what Johnny has worked out is dy/d x * 1/y (where y = f(x)
i answered your question in your last post lilon
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i've had another look at this lilon and the answer according to your teacher is right = as you say multiplied by the original equation dy/dx = e^2x[2 +2x^2 + x - 4(1 + x^2)csc2x] / (1+x^2)^1/2*tan(x)^2
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