What is the average velocity of the particle during the first two minutes? s(t) = 16t^3 + 12t^2-144t. t0. v(t)=48t^2+24t-144

Question

What is the average velocity of the particle during the first two minutes?   s(t) = 16t^3 + 12t^2-144t. t>0. v(t)=48t^2+24t-144

anonymous · Answer

No on e here does velocity answers i had one question on velocity, no one answered so yaa/....

turingtest · Answer

$$v_{avg}={s(t_2)-s(t_1)\over t_2-t_1}$$
so plug in$$t_2=2,t_1=0$$and you have your answer

turingtest · Answer

can you take it from here? questions?

anonymous · Answer

i did that and i kept getting the wrong answer which is why im confused :/

turingtest · Answer

let me try then and see what I get, just a sec...

anonymous · Answer

mk the answer is -56

turingtest · Answer

I got -56
(you didn't give me units)

turingtest · Answer

well, since they give us v(t) we could say$$v_{avg}=v(t_2)-v(t_1)=96-(-144)=240$$but that's pretty sneaky...

anonymous · Answer

sorry...yea thats what i kept doing. what am i doing wrogn?

turingtest · Answer

is 240 wrong as well?

anonymous · Answer

yes the only answer is -56 m/min

anonymous · Answer

ahhh i see i got the answer nowwww

turingtest · Answer

calculator error?

anonymous · Answer

could you help me with another?

turingtest · Answer

sure, repost though please

turingtest · Answer

and hook it up with a medal holmes!

anonymous · Answer

haha i was planning on it thankss!