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Simplify i^41
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\[\Huge i\]
just i^1, so i.
My crappy notes from math lol: -If you start off with i^0 you will always get 1. Add i^(4+0) and you still get 1. And so on. -Do the same for i^1 you get i. Add i^(1+4) you still get i. -Same thing for i^2 which is -1. i^(2+4) yah get -1. i^(6+4) = -1 -And lastly i^3= -i. i^(3+4) = -i. Nifty little trick to remember how to do it.
thanks!
thats an awesome trick. Thanks soo much! :)
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using et45's logic, i^41 = i^(41mod4) = i^(1) = i
Basic pattern is i^N = i^(Nmod4)
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