A circular hole has a stack of narrow boards next to it, all the length of the radius of the circle. There is nothing to attach the boards together with. What is the smallest number of boards it takes to have one span across the center of the circle?
yup
well, an equi makes a hexagon around the perimeter
then i spose there are subsequents hexs till you approach a distance across that is less than r
do we account for enough of the boards to ledge against each other or assume a magical world of impossibilities?
what do you mean by ledge?
have you ever leaned against a table to find out that you had in fact just missed the table so that you end up somewhere closer to the vacinity of the floor instead?
I suppose you could form a cantelever, I wonder if that is less than the sphincter you were describing with hexagons
how wide are the boards?
the boards are able to stack, consider that if they intersect, they are supported.
wider boards take fewer to count
Depends on the size of the hole, which isn't given
no, that length, width is a different mater
im assuming thickness is moot
it's proportinate
rxr then?
that's too wide! no fair!
Doesn't the problem statement say "narrow"?
narrow yes, but that is not very quantitative ;)
this is the math forum, not physics, shouldn't there be a theoretical answer instead of a practical one?
i spose .... just dont let osha find out
Or should I ask philosophers instead?
im getting an a in philosophy class, so i should qualify for the position
whats the measures of a 30 60 90?
1, 2, sqrt(3)
if r/2 = sqrt(3); what does 1 equal?
shrinking hexes leads to 17, which is too many, try again
1
i get r/2sqrt(3)
|dw:1318905432817:dw|
this mouse is awful
I have an answer, but keep working on it, I'd like to know what you get.
I used Geometer's Sketchpad
if i start from the middle and span outwards, i get this: |dw:1318946471472:dw|
which adds up to 15
|dw:1318947344847:dw|
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