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Mathematics 7 Online
OpenStudy (anonymous):

Look at the graph above and comment on the sign of the discriminant. Form the quadratic equation based on the information provided and find its solutions.

OpenStudy (anonymous):

OpenStudy (anonymous):

there are two zeros so the discriminant is positive

OpenStudy (anonymous):

this one is hard...

OpenStudy (anonymous):

lol @hero

OpenStudy (anonymous):

I hope this is the LAST GRAPH question for the last two weeks of this class

OpenStudy (anonymous):

its not.

OpenStudy (anonymous):

it can't be. Its too simple.

OpenStudy (anonymous):

There are two real solutions therefore the discriminant is positive. Yes it is that simple lol.

OpenStudy (anonymous):

I don't understand.. How do I find its solutions?

OpenStudy (anonymous):

The solutions are \[x = .67\] and \[x = -.16\] Solutions are where the graph crosses the x axis.

OpenStudy (anonymous):

Now its starting to make sense. But still really confused. lol

OpenStudy (anonymous):

Do you have to find the equation of the graph too??

OpenStudy (anonymous):

What is confusing and i will try to explain.

OpenStudy (anonymous):

Comment on the sign of th

OpenStudy (anonymous):

e discriminate. Form the quadratic equation based on the information, and find the solutions.

OpenStudy (anonymous):

Oh ok.. So do you understand how we can tell if the discriminant is positive?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

What you have is a Quadratic Function

OpenStudy (anonymous):

And to solve a Quadratic Function you use the Quadratic Formula

OpenStudy (anonymous):

\[\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] This is the Quadratic Formula

OpenStudy (anonymous):

The Discriminant is \[b^2 - 4ac\]

OpenStudy (anonymous):

If the discriminant is negative, then you will be taking square root of a negative number which is imaginary or complex

OpenStudy (anonymous):

And if the discriminant is positive then the square root of a positive number is a real number. The solutions in the graph are real because they dont contain the imaginary "i" therefore we can say the discriminant is positive.

OpenStudy (anonymous):

ok. That makes sense.

OpenStudy (anonymous):

Thats all I had to do???

OpenStudy (anonymous):

Yep thats it.

OpenStudy (anonymous):

I did that 5 times thinking it was incorrect!!! GRRRR Thank you so very much!

OpenStudy (anonymous):

No problem! Do you understand what all i did?

OpenStudy (anonymous):

oh wait just a sec.

OpenStudy (anonymous):

I wasnt paying attention. Your solutions are \[x = -1\] and \[x = .67\] so you FOIL\[(x + 1)(x-.67)\] together.

OpenStudy (anonymous):

I do understand, I am snipping this so I can add it to my notes. THANKS A BUNCH!

OpenStudy (anonymous):

\[x^2 -.67x + x -.67\] Add like terms and you get \[x^2 + .33x -.67\] That is the correct equation.

OpenStudy (anonymous):

THANK YOU SO MUCH!!!

OpenStudy (anonymous):

No problem!!

OpenStudy (anonymous):

I deleted what i told you wrong so you have all right information so you can re-snip it and not get confused later on.

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