f(x)=(x^3-2x^2)/(x-2)

Find the value(s) of x for which the function is discontinuous. Label each as removable or non-removable.

Could you also explain the difference between the two?

Question

f(x)=(x^3-2x^2)/(x-2)

Find the value(s) of x for which the function is discontinuous. Label each as removable or non-removable.

Could you also explain the difference between the two?

anonymous · Answer

Is the
answer 2

anonymous · Answer

the function is discontinuous at 2, it is removable. This is because the top also becomes 0 when the bottom becomes 0.

anonymous · Answer

so when finding lim->2, the answer is that the limit doesn't exist because there's a hole?

anonymous · Answer

oh u
mean to say that now the function is is in 0/0 form which is one of the indeterminate form??

jhonyy9 · Answer

x2(x-2)
------- = x2
   x-2