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How do you find the derivative of 1+2^(4-t) ?
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the one will disappear. you can set 4-t=u so you have 2^u
then you would get ln (2)*2^u*du ln (2)*2^(4-t)*(-1) -ln (2)(2^(4-t))
Let u = 4 - t du/dx = -1 dy/dx = 2^(4-t) ln 2 (-1) = -(ln2)[2^(4-t)]
and the answer gets repeated.
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