Log(3x)3=log(x^2)3
x=3
Yea , really hard to figure out . Actually i was hoping for a solution .
Is it log(3x)(3) on the left side? or [log(3x)]^3 ?
It is log(3x)(3)
ok,then that is the same as\[3 \log (3x)=3\log(x^2)\]using log properties:\[\log(27x^3)=\log(x^6)\]raise ten to both sides:\[27x^3=x^6\rightarrow27=x^3\]\[x=\sqrt[3]{27}=3\]if you didn't follow me tell me where you got lost :)
Did you solve these with logarithm base 10 or with bases (3x) and (x^2) ?
I assumed they were base ten logs, but it doesn't matter because if they were base 2 or 50 they would still cancel. if we had log(x)=y then we need to know what the base is (call it n), because after raising both sides to that power we get x=n^y but as long as it's log(x)=log(y) regardless what the base is we can infer x=y PS I have never seen a log with an x^2 base, so don't expect one anytime soon.
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