Question

how do you do the Rational Zero Test?

Answer 1

http://www.purplemath.com/modules/rtnlroot.htm

Answer 2

given an equation: \(A_nx^{n}+A_{n-1}x^{n-1}+...A_1x+A_0\)

the rational zeros will be the pool of options we get from dividing off the \(A_n\) to consider the ratio: \(\cfrac{A_0}{A_n}\)

Answer 3

otherwise it goes into something ugly with radicals and such

Answer 4

*will be in ...

Answer 5

When do you use these equations?

Answer 6

when you want to find a bunch of possible options to test out

Answer 7

spose our logical options come from {2,3,6} we would know no to waste our time trying out other numbers

Answer 8

what is the difference between rational and irrational zeros

Answer 9

rational zeros have a structure that can be tested for; whereas irrationals have no defined structure

Answer 10

a rational number is of the form: \(\cfrac{p}{q}\) where p and q are integers and q doesnt equal 0

Answer 11

irrationals are valid roots, but have no set structure to base them from

Answer 12

if asked to find the rational zeros of f(x)= x^4 - (25/4)x^2 + 9= (1/4)(4x^4-25x^2+36) where would you begin?

Answer 13

get it all to one side thru algebraic means to begin with so that you can form it into a one sided equation

Answer 14

4[x^4 - (25/4)x^2 + 9= (1/4)(4x^4-25x^2+36)]

4x^4 - 25x^2 + 36= 4x^4-25x^2+36

-25x^2= -25x^2

ummm, is this a set of equations or is this something that youve already worked on?

Answer 15

It was a question for homework, haven't already worked on it

Answer 16

as is, its 2 equations of the same curve so they intersect each other at all points

Answer 17

usually, there isnt 2 equations to work from unless your trying to find common points of intersection

Answer 18

all the directions claim is find the rational zeros of the following polynomial function, which i wrote above

Answer 19

\[f(x)= x^4 - \frac{25}{4}x^2 + 9= \frac{1}{4}(4x^4-25x^2+36)\]
and it looks like this?

Answer 20

this looks more like its a function in progress

Answer 21

that is exactly whats on my homework paper. but as you can tell i am pretty lost, but i do agree.

Answer 22

i'm in pre calc if that makes any difference

Answer 23

if you can attach a picture of youre homework as a file in here, it would help me out to see if im missing something

Answer 24

the only difference that i am able to pick up between the equation you wrote above and the one on my paper is that instead of "f(x)" my paper says P(x)

Answer 25

thats just a matter of name and not of substance

Answer 26

the only difference that i am able to pick up between the equation you wrote above and the one on my paper is that instead of "f(x)" my paper says P(x)

Answer 27

yea i didnt think that mattered, this problem is jank, my profesor is stupid, i swear he doesnt even know what hes teaching

Answer 28

well, im at an impasse on it. Good luck with it :)