|x + 2| + 16 = 14 x = −32 and x = −4 x = −4 and x = 0 x = 0 and x = 28 No solution
you cant negate an absolute value
I know.
\[|something| \neq negative something \]
| | = -# not good
sites still going slow
so what happens when you subtract 16 on both sides don't we have |junk|=negative something?
???
|x+2| +16=14 -16 -16 |x+2|=-2 x+2=-2 -2 -2 x=-4 I don't know how you got the second part but that's how i would do the first part
|x+2|=-2 never happens for any input
|something| is either positive or neutral
|something| is never negative
What do you mean? you just drop you absolute value and subtract 2 on both sides to cancel out the 2 on the side with the variable. and only |inside| has to positive..everything outside the | | can be whatever
we can put anything into | | and the output will either be 0 or positive
| | represents distance
distance is either positive or zero
distance is never negative
| | is called absolute value.. look it up on google.. Are you talking about highschool algebra or college?
absolute value is the distance of some number to 0
|-3|=3 |0|=0 |3|=3 |-141441|=141441 look the outputs are never negative
So the answer is no solution ?
That's what i'm saying.. I didn't put a negative inside the bars i put them on the outside
butter ask yourself can you ever get a negative output for |something| the answer is no
|junk| is never negative
\[|junk| \neq negative something \]
I know that... i didn't make |junk| negative it was still positive
I know that an absolute value can never be negative!
then what you know there is no solution
to this equation you have
Okay, thank you. Just making sure.
\[|x+2| \neq -2 \]
see there is no negative except on the OTHERSIDE of the = sign.. and you can do that..
no you cannot |junk| is never negative
|x+2|=-2 has no solution
|dw:1318992395252:dw|
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