Question

Solve for x
e^(2x + 5) - 5 = 0
Please show steps

Answer 1

add 5 to both sides

Answer 2

write 5 as
\[e^{\ln(5)}\]

Answer 3

so we have
\[e^{2x+5}=e^{\ln(5)}\]

Answer 4

e^(2x+5) = 5
(2x + 5) ln e = ln5
2x + 5 = ln5/lne
x = ((ln 5/ln e) - 5) / 2

Answer 5

since the bases are the same
then the exponents are the same

Answer 6

\[2x+5=\ln(5) => 2x=\ln(5)-5 => x=\frac{\ln(5)-5}{2}\]