Two forces act on a 1250 kg sailboat as it moves through the water with an initial velocity of 11 m/s. The forward force of the wind exerts 3.90*10^3 N while the resistive drag force of the water exerts 4.35 * 10^3 N. What's the velocity of the boat 15 seconds later?

Question

anonymous · Answer

resultant force on the boat =  3.9 *10^3 - 4.35*10^3 = - 0.45* 10^3 N so the boat is decelerating
-0.45* 10^3 = 1250 * a                (newtons 2nd law)
a = -0.45*10^3 / 1250 =   -0.36 m/s/s

using v = u + at
             =  11 - 0.36*15
              =  5.6 m/s

anonymous · Answer

OHMEHGLOB! THANK YOU SO MUCH!!