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Mathematics 7 Online
OpenStudy (anonymous):

Area under a graph problem

OpenStudy (anonymous):

Where is the problem?

OpenStudy (anonymous):

1 second haha

OpenStudy (anonymous):

just draw rectangles below the curve, find the areas of those rectangles, and add them up!

OpenStudy (a_clan):

integrate over the extremes

OpenStudy (anonymous):

Taking a photo of the graph now, 1 second

OpenStudy (anonymous):

If it's not a complicated graph, you can just give us the equation and the upper and lower limits etc.

OpenStudy (anonymous):

The graph shows the acceleration (rate of change of velocity) of a bullet as it is fired from the barrel of a rifle. Use the graph to calculate the speed at which it leaves the rifle (the muzzle velocity)

OpenStudy (anonymous):

It's the area of that half-ellipse.\[A_{ellipse}=\frac{1}{2}*\pi * x*y\]where x is 5s and y is 60000 ms^-2 (if I am reading it correctly)

OpenStudy (anonymous):

Oh okay cool, I'll give that a go

OpenStudy (anonymous):

or actually, where x is 2.5s and y is 60000

OpenStudy (anonymous):

that is one powerful rifle.

OpenStudy (kira_yamato):

For me I'll use integrals (definite)

OpenStudy (a_clan):

If we do not have the equation of curve or we do not know exactly if the figure is a standard curve(i.e. ellipse here), Then the area under curve should be calculated by adding all the full squares, on graph paper under curve, with partial-squares as triangles. We only get approximate answer with this method.

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