Area under a graph problem
Where is the problem?
1 second haha
just draw rectangles below the curve, find the areas of those rectangles, and add them up!
integrate over the extremes
Taking a photo of the graph now, 1 second
If it's not a complicated graph, you can just give us the equation and the upper and lower limits etc.
The graph shows the acceleration (rate of change of velocity) of a bullet as it is fired from the barrel of a rifle. Use the graph to calculate the speed at which it leaves the rifle (the muzzle velocity)
It's the area of that half-ellipse.\[A_{ellipse}=\frac{1}{2}*\pi * x*y\]where x is 5s and y is 60000 ms^-2 (if I am reading it correctly)
Oh okay cool, I'll give that a go
or actually, where x is 2.5s and y is 60000
that is one powerful rifle.
For me I'll use integrals (definite)
If we do not have the equation of curve or we do not know exactly if the figure is a standard curve(i.e. ellipse here), Then the area under curve should be calculated by adding all the full squares, on graph paper under curve, with partial-squares as triangles. We only get approximate answer with this method.
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