OpenStudy (anonymous):

help.. dy/dx-y=x+1

6 years ago
OpenStudy (anonymous):

what are we finding?

6 years ago
OpenStudy (anonymous):

dont know how that got there?

6 years ago
OpenStudy (anonymous):

looks like a partial derivative?

6 years ago
OpenStudy (anonymous):

oh so you mean we are finding dy/dx of the -y=x+1 ?

6 years ago
OpenStudy (anonymous):

isn't it y = -x - 1 dy/dx = -1?

6 years ago
OpenStudy (anonymous):

y = the expression i wrote

6 years ago
OpenStudy (anonymous):

I'm still confused about the question though. Not exactly sure what math this is.

6 years ago
OpenStudy (anonymous):

differential equation.. you have to find y

6 years ago
OpenStudy (anonymous):

with respect to x

6 years ago
OpenStudy (anonymous):

oh ODE ;D

6 years ago
OpenStudy (anonymous):

So the integrating factor is e^(-x)?

6 years ago
OpenStudy (anonymous):

yes you are right .. i was wrong forgot about the -1

6 years ago
OpenStudy (anonymous):

im assuming that f(x,y) = y + x + 1 so the answer would be 1

6 years ago
OpenStudy (anonymous):

integrating factor :e^-x so: \[((∫e^-x∗(x+1))+C)/e^-x\]

6 years ago
OpenStudy (anonymous):

corey89 I thin it's is a differential equation problem like Coolsector said

6 years ago
OpenStudy (anonymous):

agreed

6 years ago
OpenStudy (anonymous):

\[y(x)=c_1 e^x-x-2 \]

6 years ago