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help.. dy/dx-y=x+1
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what are we finding?
dont know how that got there?
looks like a partial derivative?
oh so you mean we are finding dy/dx of the -y=x+1 ?
isn't it y = -x - 1 dy/dx = -1?
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y = the expression i wrote
I'm still confused about the question though. Not exactly sure what math this is.
differential equation.. you have to find y
with respect to x
oh ODE ;D
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So the integrating factor is e^(-x)?
yes you are right .. i was wrong forgot about the -1
im assuming that f(x,y) = y + x + 1 so the answer would be 1
integrating factor :e^-x so: \[((∫e^-x∗(x+1))+C)/e^-x\]
corey89 I thin it's is a differential equation problem like Coolsector said
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agreed
\[y(x)=c_1 e^x-x-2 \]
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