Question

Say I have the compound:
Pb(C2H3O2)3.

How do I determine the oxidation states?
I know I split it up into ions:

(C2H3O2)1-
According to the rulings,
OX[H] = +1
OX[O] = -2
So then:
2x + 3(+1) + 2(-2) = -1
2x + 3 -4 = -1
2x - 1 = -1
2x = 0
x = 0? Where x represents OX[C]. Is it by all means possible to have an oxidation number of 0?

Answer 1

Also, is the oxidation state of PB3+:
OX[Pb] = +3?