Jacqui has grades of 78 and 87 on her first two algebra tests. If she wants an avergae of at least 76, what possible scores can she make on her third?

Question

anonymous · Answer

76 >= (78 + 87 + t)/3
228 >= 78 + 87 + t
228 >= 165 + t
63 >= t
SO she must get a 63 or above

anonymous · Answer

I think the > is in the wrong direction but the answer is right

amistre64 · Answer

$$\frac{\sum(priors)+new}{\#priors+1}\ge76$$

$$\sum(priors)+new\ge76(\#priors+1)$$

$$new\ge76(\#priors+1)-\sum(priors)$$

maybe

amistre64 · Answer

this is greater than or equal to that ... it fits

anonymous · Answer

Great thanks a lot:)

anonymous · Answer

sorry I am a bit confused so she has to get 63 or greater or greater than 63

amistre64 · Answer

yes, they have to make at least a 63 to average out to a 76.  anything less than that will not do.