Question

f(x) = –x^3 + 2 how do I find the turning point?
Or do I just look for order pairs?

Answer 1

do you know derivatives?

Answer 2

No :/

Answer 3

then i guess try and graph it with points

Answer 4

But do I only find the turning point when it is in parentheses right?

Answer 5

not sure what you mean, the turning point is when slope = 0

Answer 6

how did you get that answer?

Answer 7

i differentiate f(x) and set it equal to zero to get -2x^2=0, then solving for x you get x = 0 then sub x=0 into the original F(x) you get f(0) = -0^3 +2 , so then you have (0,2) being the turning point

Answer 8

otherwise you could say x^3 has turning point at (0,0), so does -x^3, then if you shift it up to you get (0,2) as the turning point

Answer 9

shift it up two*

Answer 10

Oh ok Thank you :))