In the equation 2x' dt, is dx/dt equivalent to x' ??
Are you trying to differentiate with respect to t(time)?
yes!
so whats your problem list it so i can help you step by step please
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okay so I'm looking at an example problem and the example goes from the equation 2 x' dt and then the next step it shows 2 dx. I'm just wondering if its because x' = dx/dt in this situation
The original equation is 2x' dt and its w.r.t. time sorry if i'm not making much sense
does it go from 2x' to dx/dt because dx/dt = x' you can write it either way
it goes from 2x' dt then it is 2 dx I feel like it's because since the x' = dx/dt then that would mean (dx/dt) * dt so both the time differentials cancel. is that right? or is my assumption wrong
yeah that makes sense, what chapter are you on and whats it going over?
thanky!! its a small part of a line integral of a vector field problem and i'm just reviewing some differential equations as a refresher because the calculus has kinda faded from me
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