Question

Find the first TWO non-negative asymptotes and the first negative asymptote of the graph of y in radians

y=tan(3x)

smallest non-negative asymptote: x=
second non-negative asymptote: x=
first negative asymptote: x=

Answer 1

smallest non-negative asymptote: x= pi/6
second non-negative asymptote: x= pi/6 + pi/3 = pi/2
first negative asymptote: x= -pi/6

inflection point (on the midline at x=0
period = pi/3

Answer 2

omg thanks can you help me with more of the same type of questions pls

Answer 3

I'll try

Answer 4

ok let me type em up

Answer 5

heres another one
Find the first TWO non-negative asymptotes and the first negative asymptote of the graph of y in radians

y=cot(x−π/3)
smallest non-negative asymptote: x=
second non-negative asymptote: x=
first negative asymptote: x=

Answer 6

period = pi

smallest non-negative asymptote: x= pi/3 (this is the shift to the right)
second non-negative asymptote: x= pi/3 + pi = 4pi/3
first negative asymptote: x= pi/3 - pi = 2pi/3

Answer 7

wow man thanks for the help. i have 4 more of these types of question...do you have the time man? i dont want to bother you

Answer 8

let's go

Answer 9

Find the first TWO non-negative asymptotes and the first negative asymptote of the graph of y in radians

y=sec(3x).
smallest non-negative asymptote: x=
second non-negative asymptote: x=
first negative asymptote: x=

Answer 10

period =2pi/3
the asymptotes will occur where the cos[3x] is equal to 0:

smallest non-negative asymptote: x= pi/6
second non-negative asymptote: x= pi/2
first negative asymptote: x= -pi/6

Answer 11

Find the first TWO non-negative asymptotes and the first negative asymptote of the graph of y in radians

y=csc(x/5).
smallest non-negative asymptote: x=

second non-negative asymptote: x=

first negative asymptote: x=

Answer 12

period = 10pi
there is no horizontal shift so
smallest non-negative asymptote: x= 0
second non-negative asymptote: x= 5pi (half way from 0 to 10pi)
first negative asymptote: x= -5pi (half way from 0 to -10pi)

Answer 13

Find the first TWO non-negative asymptotes and the first negative asymptote of the graph of y in radians

y=2sec(x−π/3)+1.
smallest non-negative asymptote: x=

second non-negative asymptote: x=

first negative asymptote: x=

Answer 14

y=2sec(x−π/3)+1.
The 2 and the +1 do not have anything to do with the asymptotes
period = 2pi

smallest non-negative asymptote: x= 5pi/6
second non-negative asymptote: x= 11pi/6
first negative asymptote: x= -pi/6

Answer 15

Find the first TWO non-negative asymptotes and the first negative asymptote of the graph of y in radians

y=−8csc(5x+π/8)−2.
smallest non-negative asymptote: x=

second non-negative asymptote: x=

first negative asymptote: x=

Answer 16

Sorry, I've gtg for a short while so this is the last one I can help you with or now.

y=−8csc(5x+π/8)−2.
period = 2pi/5
half period =pi/5

NOTE ORDER OF ANSWERS CHANGED...

first negative asymptote: x= -pi/8 (horizontal shift left)
smallest non-negative asymptote: x= -pi/8 + pi/5 = 3pi/40
second non-negative asymptote: x= 3pi/40 + pi/5 = 11pi/40

Answer 17

yea none none worked

Answer 18

its -9csc(5x+pi/9)-2

Answer 19

help please?