Question

Find the first TWO non-negative asymptotes and the first negative asymptote of the graph of y in radians y=−8csc(5x+π/8)−2. smallest non-negative asymptote: x= second non-negative asymptote: x= first negative asymptote: x=

Answer 1

Find the first TWO non-negative asymptotes and the first negative asymptote of the graph of y in radians y=−8csc(5x+π/8)−2.

smallest non-negative asymptote: x=
second non-negative asymptote: x=
first negative asymptote: x=

Answer 2

hey i'm back sooner than i thought; did i make a mistake? you are posting the last question i answered

Answer 3

none of the answer work

Answer 4

i donno why

Answer 5

on the one you reposted?

Answer 6

this one at the top of the page

Answer 7

sorry, I found my mistake post following

Answer 8

ok thx

Answer 9

y=−8csc(5x+π/8)−2
I missed the NEGATIVE in front of the 8 (plus another error)
period=2pi/5
half period = pi/5 = 8pi/40
ANSWER ORDER CHANGED
first negative asymptote: x= -pi/40 (shift left)
smallest non-negative asymptote: x= pi/40 + pi/5 = 7pi/40
second non-negative asymptote: x= 7pi/40 + pi/5 = 15pi/40 = 3pi/8

Answer 10

yea they worked thx for the help
this is the last one if you dont mind

Find the first TWO non-negative asymptotes and the first negative asymptote of the graph of y in radians

y=10tan(5x−π/10).

smallest non-negative asymptote: x=

second non-negative asymptote: x=

first negative asymptote: x=

Answer 11

y=10tan(5x−π/10)
period = pi/5; half period = pi/10
Inflection point at x=pi/50
smallest non-negative asymptote: x= pi/50 + pi/10 = 6pi/50 = 3pi/25
second non-negative asymptote: x= 3pi/25 + 5pi/25 = 8pi/25
first negative asymptote: x= 3pi/25 - 5pi/25 = -2pi/25

Answer 12

wow thanks very much for all the help

Answer 13

ur welcome :})