Question

need help on the attachment

Answer 1

pdf

Answer 2

G doesn't matter. Because the function squared is always positive. So just factor the polynomial. (x-3)(2x+4)(1+g^2) so x=3 or x=-2

Answer 3

so the function is just (x-3)(2x+4)? Also do I plug in test point for this function to check for a local max or min

Answer 4

to find the local max find where the slope goes from increasing to decreasing. and you would use test points

Answer 5

but what is the current function because the thing that is confusing me is (1+g^2)

Answer 6

yeah, im not totally sure about that. im just in calc 1 also. but im pretty sure malevolence was right in saying that it doesn't matter, because you are looking to see if the slope is negative or positive, and 1+g^2 would always be positive, so it would have any effect on the outcome when you are just checking to see if its negative or positive

Answer 7

but don't I need to take the derivative of the function before I can check to see the relative min or max

Answer 8

it already gives you f'(x), so you just need to find zeros of f'(x), the check test points inbetween them, and see if it ends up negative or positive. just ignore (1+g^2), because it will always be positive

Answer 9

did you just get local max x=-3

Answer 10

x=-2

Answer 11

he factored it wrong ta go to your other post... you posted this twice i wrote the answers

Answer 12

the factors should be (2x+6)(x-2)

Answer 13

ohh, ok yeah in that case, x=-3