Question

isthat right?: lim (x->infinity) (e^-6x)=infinity

Answer 1

The solution will tend to 0 because the coefficient of x in the exponential is negative. As x gets larger, the -6x part gets more and more negative, so tends to zero.

Answer 2

Polrek is correct you can lok at e^-6x as this

\[e^{-6x}=\frac{1}{e^{6x}}\] so as x gets greater , the denominator gets larger and goes to 0

Answer 3

hope this helps =]

Answer 4

Good way of describing it in simpler detail. Thanks :)