Question

Formula to find a point (0,y) that is equidistant from (6,1) and (-1, -2)

Answer 1

Do the distance of the first point with the second one.
Then do the first point of the first point with the third one.

You'll get two expressions.

First expression = second expression.

Solve for y, and you'll get it.

Answer 2

using protractor is easy

Answer 3

\[d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\]
since they are equidistant
\[\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}=\sqrt{(x_{2}-x_{3})^{2}+(y_{2}-y_{3})^{2}}\]
\[\sqrt{(0-6)^{2}+(y-1)^{2}}=\sqrt{(0-(-1))^{2}+(y-(-2))^{2}}\]

Answer 4

I dont understand any answer, Sorry. Im really bad at math anyway to dumb it down