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Mathematics 8 Online
OpenStudy (anonymous):

one divided by zero is what?

OpenStudy (agreene):

undefined

OpenStudy (anonymous):

so what will i write as my answer now? lol

OpenStudy (agreene):

1/0 = undefined

OpenStudy (anonymous):

k

OpenStudy (anonymous):

This is actually known as division by zero,read more here: http://en.wikipedia.org/wiki/Division_by_zero

OpenStudy (anonymous):

hahahha ok i have read it,then i guess i will write my answer as undefined

OpenStudy (anonymous):

If you are mentioning a / 0 where a is any number than this is undefined. If you are referring to 0 / a where a is any number then you always have 0. The proof of division by zero is actually pretty cool. Watered down version of the proof of division by zero being undefined. Suppose that you have a / b = 0 where a and b are any number. Then a = b(0) Then a = 0 But then 2a = 0 as well, and this is true for any number. So it makes no sense to define division by zero.

OpenStudy (agreene):

If you are not in calculus yet, just write undefined. If you are in calc I or II talk about l'hopitals... anything higher and you would probably know what you need to look up.

OpenStudy (anonymous):

that's precalculus,the question goes like this given f(x)=x/(x+1), find f(0)

OpenStudy (anonymous):

i meant find f(-1)

OpenStudy (anonymous):

Okay, so if you are looking for f(-1), then you plug in -1 wherever there is an x. -1/(-1+1) This is -1/0, which is undefined. Since you are not in calc, there is no other way to do this.

OpenStudy (anonymous):

oh! so it's calculus u can solve further? anyway is just functions

OpenStudy (anonymous):

ok using the same given function, find f(x+h)

OpenStudy (agreene):

In this case, you cannot progress any further using calculus. In situations where you have 0/0 or infty/infty you can use l'Hopitals rule and come to a different answer.

OpenStudy (anonymous):

f(x+h) would be the difference quotient: Assuming you are talking about limits, we have: limit h->0 (x+h)/(x+h)+1 which is lim h->0 (x+h)/(x+h-1) This just becomes your original function again of x/x+1. Makes no good sense.

OpenStudy (anonymous):

but i just substituted f(x+h) into the given function and got this as my answer x+h/(x+h+1)

OpenStudy (anonymous):

so what's the answer now?

OpenStudy (anonymous):

That is the answer. If you are just substituting. I was not sure given the context if you were taking the limit or just substituting the difference quotient (x+h). If you are just plugging in, then x+h/(x+h+1) is correct. Cheers!

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