Question

Determine the zeros of f(x) = x3 – 3x2 – 16x + 48. (1 point)

Answer 1

you can factor this

Answer 2

gcf of x^3,3x^2 is x^2
gcf of 16x,48 is 16

Answer 3

so factor the first two terms by writing x^2(something)
minus
so factor the second two terms by writing 16(something)
so we have x^2(something) - 16(something)
=(something)(x^2-16)
=(something(x-4)(x+4)

Answer 4

x2(x-3)-16(x-3)=(x2-16)(x-3)
x2=16
x_1,_2=+/-4
x_3=3

Answer 5

ok, but the answers I got were x=-4 x=3 and x=4
So I did get them right?

Answer 6

thats what he has

Answer 7

Awesome, thanks guys, I checked it and yeah its tht c: