Question

deduce that \[\lim_x\rightarrow\infty{\frac{x^2}{n!}}\] = 0 for all x

Answer 1

the question is wrong... here it is again:\[\text{Deduce that }\lim_{n\rightarrow\infty}{\frac{x^2}{n!} = 0}\text{ for all x}\]

Answer 2

it's still wrong, it must be x^n and not x^2 :-( I'm sleepy

Answer 3

ok...that better

Answer 4

show that the series \[\sum_{n=1}^{\infty}\frac{x^n}{n!}\]

has radius of convergence of infinity. then the limit of the sequence has to be zero

Answer 5

I have shown it, so do I just say that 'since that converges for all x, then for all x the limit of the sequence must be 0'

Answer 6

if it wasn't zero for a specific value of x then the series would not converge by the divergence test

Answer 7

right

Answer 8

alright I'm done with math.
\begin{array}l\color{#FF0000}{\text{Y}}\color{#FF0000}{\text{ }}\color{#FF7F00}{\text{i}}\color{#FF7F00}{\text{ }}\color{#FFE600}{\text{p}}\color{#FFE600}{\text{ }}\color{#00FF00}{\text{p}}\color{#00FF00}{\text{ }}\color{#0000FF}{\text{e}}\color{#0000FF}{\text{ }}\color{#6600FF}{\text{e}}\color{#6600FF}{\text{ }}\color{#8B00FF}{\text{!}}\color{#8B00FF}{\text{ }}\color{#FF0000}{\text{!}}\color{#FF0000}{\text{ }}\color{#FF7F00}{\text{!}}\color{#FF7F00}{\text{ }}\end{array}
no just kidding I will do 6 more chapters again tomorrow :-P

Answer 9

nice

Answer 10

My fault for missing 3 weeks of school

Answer 11

that's not good

Answer 12

hope you had fun at least!