Question

Help with Geometry type question!! File will be attached!

Answer 1

121*2=242

Answer 2

But how?!?!?

Answer 3

(sqrt(11^2-b^2))^2+b^2+11^2=11^2+11^2=242. if you like it choose as good answer

Answer 4

\[(\overline{AC})^2+(\overline{CB})^2=(\overline{AB})^2\]
\[(\overline{AD)}^2+(\overline{DC})^2=(\overline{AC})^2\]
we want to find \[(\overline{AB})^2+(\overline{CB})^2+(\overline{DC})^2+(\overline{AD})^2\]

Answer 5

\[\overline{AB}=11\]

Answer 6

so we have
\[(11)^2+(\overline{CB})^2+(\overline{DC})^2+(\overline{AD})^2\]
but what is this other junk

Answer 7

\[(\overline{AC})^2+(\overline{CB})^2=(\overline{AB})^2 \]
we can solve for length CB

Answer 8

and i will solve for length CB squared

Answer 9

\[(\overline{CB})^2=(\overline{AB})^2-(\overline{AC})^2=(11)^2-(\overline{AC})^2\]

Answer 10

so now we have
\[(11)^2+(\overline{CB})^2+(\overline{DC})^2+(\overline{AD})^2 \]
=
\[(11)^2+(11^2-(\overline{AC})^2)+(\overline{DC})^2+(\overline{AD})^2\]

Answer 11

but the other equation also had length AC right?

Answer 12

recall
\[(\overline{AD)}^2+(\overline{DC})^2=(\overline{AC})^2 \]

Answer 13

\[(11)^2+(11^2-[(\overline{AD})^2+(\overline{DC})^2])+(\overline{DC})^2+(\overline{AD})^2\]

Answer 14

\[2 \cdot 11 ^2 -(\overline{AD})^2-(\overline{DC})^2+(\overline{DC})^2+(\overline{AD})^2\]
what happens here though?

Answer 15

we get
\[2(121)+0+0\]

Answer 16

2(121)=242