Question

A catcher stops a ball travelling at 26.2 m/s in a distance of 85.1 cm and feels a force of 313 N against his glove. What is the mass of the ball?

Answer 1

first find the acceleration:

\[Vf^2 - Vi^2 = 2a(Xf-X i)\]\[(0m/s)^2 - (26.2 m/s)^2 = 2a(0 - 0.851m)\]\[\frac{-686.44}{2} = -343.22 = a(-0.851m)\]\[\frac{-343.22}{-0.851m}=~403 m/s^2\]
Since force = mass times acceleration:
\[313N = mass * 403m/s^2\]\[\frac{313N}{403} m/s^2 = 0.777kg\]

Answer 2

In the last statement, the m/s^2 on the left should be in the denominator of the fraction...I guess I made a typo