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Mathematics 6 Online
OpenStudy (anonymous):

I WANT TO ASK ABOUT LINEAR TRANSFORMATION

OpenStudy (anonymous):

what u wanna ask?

OpenStudy (anonymous):

if the question like this L(x,y)=(x+y,x-y) how can i know that it is a linear transformation???

OpenStudy (anonymous):

A transformation \(L: V \rightarrow W\) is said to be linear if it has the following two properties: 1) \(L(v+u)=L(v)+L(u) \text{, u and v are two vectors in V.}\) 2) \(L(cv)=cL(v) \text{, v is a vector in V and c is a constant.}\)

OpenStudy (anonymous):

Now let's see weather the transformation we have is linear or not by testing it to each property. Let \((x_1,y_1)\in v \text{ and } (x_2,y_2)\in u\), then: 1) \(L(u+v)=L(x_1+x_2,y_1+y_2)=(x_1+x_2+y_1+y_2,x_1+x_2-(y_1+y_2))\) \(=(x_1+y_1,x_1-y_1)+(x_2+y_2,x_2-y_2)=L(v)+L(u).\) 2) \(L(cv)=L(cx_1,cy_1)=(cx_1+cy_1,cx1-cy_1)=c(x_1+y_1,x_1-y_1)=cL(v).\) We can see that the it satisfies both properties and therefor \(L\) is a linear transformation.

OpenStudy (anonymous):

I meant: let \(v=(x_1,y_1) \text{ and } u=(x_2,y_2)\). That doesn't affect the answer anyway.

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