Question

solve ordinary differential equation
(1-x^2)y'-2xy^2=xy

Answer 1

This equation is separable; see how to do that and then you're in the home stretch.

Answer 2

James could you kindly please go through the workings, i am studying this at the moment as well.

Answer 3

We want to write y' = F(x,y) = g(x)h(y)

Answer 4

I got \[dy/(2y ^{2}-y)=xdx/(1-x ^{2})\]

Answer 5

Because if we can, then \( dy/h(y) = g(x) dx \) and we can integrate.

Answer 6

Yes, almost right. Check your signs carefully.

Answer 7

I found a mistake :)

Answer 8

\[ (1-x^2) y' = x (y + 2y^2) \]

Answer 9

and then we express y from the result and that's it?

Answer 10

yes.

Answer 11

thanks :) can I give some problems more? can I attach a file?

Answer 12

For example, the integral of the x side is \( -(1/2) \ln(1-x^2) + C \)

No .... I'm off to buy my new iPhone right now.

Answer 13

Sorry ;-)

Answer 14

u can do it later? :)

Answer 15

I'll probably be around later, yes.

Answer 16

ok :) thanks :) good luck in shopping ;)