Question

If A = {integers divisible by 2} and B = {integers}, what is A ∩ B?

Answer 1

A. Because A is a subset of B.

Answer 2

.... That didn't answer much of my question, sorry.

Answer 3

A = {integers divisible by 2} because this collection of terms is also included in set B.

Answer 4

It's a multiple choice question,

{…-3, -2, -1, 0, 1, 2, 3 …}

{ }

{0}

{… -6, -4, -2, 0, 2, 4, 6 …}

Answer 5

Basically what william is saying is that


A ∩ B = A


since EVERY element of set A is in set B

Answer 6

By definition the intersection of two sets A and B, \(A \cap B\) is the set of objects which are members of both the set A and the set B.

In this case, because every member of the set A is also a member of set B, the intersection of these two sets is exactly equal to the set A.

Answer 7

More formally,


If set A is a subset of B, then A ∩ B = A

Answer 8

So, then there is no answer?

Answer 9

we didn't say that

Answer 10

No, now the question is out of the options you have listed, which one is set A.

And I really think you should try and figure that out without us saying, although we'll tell you if you're right.

Answer 11

But, A isn't in the options.

Answer 12

lol

Answer 13

ah notation confusion....lol


set A is just a name for a set of numbers which is NOT choice A (two different things...)

Answer 14

call it set X if you have to

Answer 15

Hence which option listed is the set A = {integers divisible by 2}:

{…-3, -2, -1, 0, 1, 2, 3 …}

{ }

{0}

{… -6, -4, -2, 0, 2, 4, 6 …}

Answer 16

the answer would basically be, {… -6, -4, -2, 0, 2, 4, 6 …} ?

Answer 17

yep

Answer 18

8D thanks, guys. c: