If point C is the midpoint of AB, what is the coordinate of point B?
A(xa, ya) B(xb,yb) C(xc,yc) \[(xa + xb)/2 = xc; (ya+yb)/2 = yc => xb = 2xc - xa, yb = 2yc - ya\]
I'm confused.
(–3, 3) (–2, 1) (–4, 4) (–4, 1)
those are the answer choices.
yep, but there aren't any coordinates...maybe you've mistaken the picture with the text? :)
my bad haha
i think that is wrong one too...that is the picture for distance of AB i guess :) here you;ll have one line, A and B on the ends, and C in the middle, as the text says
but, nevermind, i can give you instructions..A has x coordinate, so does B. to get x coordinate of C, you take Xa + Xb and divide that sum with 2. Same for y coordinate :)
nope that's the right pic. AB is supposed to have a line over it. like this:|dw:1319315769572:dw|
i just didn't know how to type it when asking the question
\[A(5,5), B(x _{b}, y _{b}), C(1,4)\] Since C is midpoint of A nd B, you use this expressions to find coordinates: \[x _{c} = (x _{a} + x _{b}) / 2\] \[y _{c} = (y _{a} + y _{b}) / 2\] Therefore: \[x _{a} = 5, y _{a} =5\] \[x _{c} = 1, y _{c} = 4\] Replace it in the expression above: \[1 = (5 + x _{b}) / 2\] \[2 = 5 + x _{b}\] \[x _{b} = 2 - 5 = -3\] Analogue for y coordinate: \[4 = (5 + y _{b}) / 2\] \[8 = 5 + y _{b}\] \[y _{b} = 8 - 5 = 3\] So, te answer is (-3,3)
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