Question

how do i go from 2x-4/sqrt of x- x^+4x+3/2x^3/2= 3x^2+4x-3/2x^3/2

Answer 1

try equation editor, this is not at all clear

Answer 2

sorry about that

Answer 3

\[(2x+4)/(\sqrt{x})-(x^2+4x+3)/(2x ^{3/2)}= (3x^2+4x-3)/(2x^3/2)\]

Answer 4

how do i go from left to right

Answer 5

looks like you are trying to subtract. one denominator is
\[\sqrt{x}\] the other is
\[2x^{\frac{3}{2}}=2\sqrt{x^3}\] multiply the first one top and bottom by
\[2x\] so that the denominators will be the same.

Answer 6

you will get
\[\frac{2x(x+4)-(x^2+4x+3)}{2\sqrt{x^3}}\]

Answer 7

last step is to remove parentheses in the numerator and combine like terms

Answer 8

isnt the sqrtof x = x^1/2

Answer 9

yes

Answer 10

\[\sqrt{x} \] = x^1/2

Answer 11

one denominator is
\[\sqrt{x}\] the other is
\[2\sqrt{x^2}\] if you multiply the first one by
\[2x\] you will get
\[2x\times \sqrt{x}=2x^{\frac{3}{2}}=2\sqrt{x^2}\]