Question

w^2-2w+1=0 solve by completing the square

Answer 1

w=1

Answer 2

\[(w-1)^2=0\]

Answer 3

\[w^2-2w=-1\]
\[(w-1)^2=-1+1=0\]
\[(w-1)^2=0\]
\[w-1=0\]
\[w=1\]

Answer 4

has to have two answers it a second degree equation

Answer 5

No, there will be just one.
this is because the curve only intersects the x-axis once,

Answer 6

1 multiplicity 2

Answer 7

okay i wrote problem wrong it is w^2-2w-63

Answer 8

=0

Answer 9

sorry

Answer 10

-63=-9*7
-2=-9+7

Answer 11

\[(w-9)(w+7)=0\]

w = 9, w = -7

Answer 12

\[(w-9)(w+7)=0\]

Answer 13

okay i just had my signs wrong and now i see where my mistake was thank you

Answer 14

you welcome.

Answer 15

okay how about w^2+2w=4 solve by factoring or completeing the square

Answer 16

i move the 4 over
so it wold become w^2+2w-4=0

Answer 17

\[\Large -1 \sqrt5, \sqrt5 -1\]

Answer 18

i would not move it over. i would write
\[w^2+2x=4\]
\[(w+1)^2=4+1=5\]
\[w+1=\pm\sqrt{5}\]
\[w=-1\pm\sqrt{5}\]

Answer 19

okay i got it i was trying to factor...but i see i can't

Answer 20

w and x?

Answer 21

this cannot be factored.

Answer 22

satellite how did you solve your equation?
oh wait does w=x?

Answer 23

lol

Answer 24

LOL.

Answer 25

okay so how about 8s-11=(2-6)(s-4)

Answer 26

8+4=16?

Answer 27

Dang!

Answer 28

lol

Answer 29

i mistyped the problems ready 8s-11=(s-6)(s-4)
i am horriable typer

Answer 30

LOL.

Answer 31

multiply the left hand side
then put everything on one side
and combine like terms

Answer 32

multiply left side or right side?

Answer 33

so i got 8s-11=s^2-10s+24

Answer 34

is that right?

Answer 35

i don't know my left from right
do whatever side that requires multiplication

Answer 36

\[\huge \checkmark\]

Answer 37

LOL.

Answer 38

yes thats right cas

Answer 39

okay so then combine the sides and i got s^2-18s_35
is that correct

Answer 40

goodnight guys
i have to read a paper
good luck cas
and i will be watching for mistakes saifoo :)

Answer 41

Good night!! :D

Answer 42

thanks and goodnight

Answer 43

\[-s^2+18 s-35 = 0 \]

Answer 44

okay so what is the next step now

Answer 45

\[s = 9-\sqrt{46} \]
\[s = 9+\sqrt{46}\]

Answer 46

how do you get that?

Answer 47

Quadratic formula!

Answer 48

okay thanks

Answer 49

no problem,

Answer 50

how about 8 plus or minus square root of -36 over 2

Answer 51

\[\frac{8 \pm \sqrt{-36}}{2}\]Like that?

Answer 52

yes

Answer 53

\[4+3i, 4-3i\]

Answer 54

all right wise guys w = x!

Answer 55

so how do it can you do it step by step for me trying to really understand it

Answer 56

\[\frac{8+ 6i}{2}, \frac{8-6i}{2}\]
\[\frac{2(4+3i)}{2},\frac{2(4-3i)}{2}\]
Both 2 cancels out,
finally,
\[4+3i, 4-3i\]

Answer 57

okay thank you. i am finally starting to feel most comfortable

Answer 58

You welcome.

Answer 59

so z^2-2z-191
1. \[-2\pm \sqrt{4^{2}}-4(1)(-191) \over 2\]

Answer 60

\[-2\pm \sqrt{4^{2}-4(1)(-191)} \over 2\]

Answer 61

okay so then it become \[2\pm \sqrt{4}-(-764)\] over 2

Answer 62

No, the square root is whole thing.

Answer 63

yes yours it correct still learning how to you it

Answer 64

use not you

Answer 65

Ohh, np

Answer 66

oksy so then it is \[2\pm \sqrt{-768} \over 2 \]

Answer 67

\[2\pm \sqrt{780} \over 2\]

Answer 68

then \[2\pm \sqrt{256 \times3} \over 2 \]

Answer 69

768 not 780

Answer 70

\[\sqrt{780} = 2 \sqrt{195}\]

Answer 71

then \[2\pm16 \sqrt{3} \over 2\]

Answer 72

it is 780.

Answer 73

are you solving
\[z^2-2z-191=0 \]?

Answer 74

not sorry trying to go to fast 768
yes

Answer 75

16+764 ===> 780

Answer 76

\[z-2z=191\]
\[(z-1)^2+191+1=192\]
\[z-1=\pm\sqrt{192}=8\sqrt{3}\]
\[z=1\pm8\sqrt{3}\]

Answer 77

if the "middle term" has an even coefficient it is much easier to complete the square. that is because you will not have a denominator that the quadratic equation forces on you

Answer 78

in any case cassy you have it because as soon as you divide your answer by the 2 in the denominator you will get
\[1\pm8\sqrt{3}\]

Answer 79

okay that makes since thanks

Answer 80

\[\Huge \checkmark\]

Answer 81

hello saifooo!

Answer 82

Hey Sat. xD
Openstudy is so low these days! :(

Answer 83

4w^2-36w+78=0

Answer 84

\[\frac12(9-\sqrt3), \frac12(9+\sqrt3)\]

Answer 85

so solving by quadratic formula right not by factor

Answer 86

Yes, that's easy. and it dosn't wastes our time.
secondly, it has less errors!

Answer 87

okay great thanks
i think i may have a few more questions

Answer 88

Sure..

Answer 89

4t^2-18t+39=0

Answer 90

do i do quad or factor

Answer 91

Quad.

Answer 92

and if i do quad whne i get to \[18\pm \sqrt{-300} \over 8\] iam lost

Answer 93

\[\huge \checkmark \]

Answer 94

now what do i do
do i factor out 300 to what?

Answer 95

\[\sqrt{-300}=\sqrt{-100 \times 3}=-10i \sqrt3\]

Answer 96

then the \[18pm10i \sqrt{3} \over 8\] is that te moreh answer or can i simply

Answer 97

is that the answer or can i simply fly

Answer 98

we can simplify by taking 2 common