Question

find (g.f)(4) for the functions below

f(x) = x+3, g(x) =1/x^2

Answer 1

\[f(4)=4+3=7\]
\[g(7)=\frac{1}{7^2}=\frac{1}{49}\]

Answer 2

that was
\[g\circ f(4)\] if it is
\[g\times f(4)\] then the answer is
\[g(4)\times f(4)=\frac{1}{49}\times 7=\frac{1}{7}\]