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Find all unit vectors parallel to the yz-plane that are perpendicular to the vector (3, -1, 2)
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if the vector is parallel to the yz plane, it must have 0 for an x component. Making an educated guess on a perpendicular vector, it would be (0, 2, 1). taking the inner product (or dot product if you like physics) of these 2 vectors gives 0, so they are perpendicular.
however, (0, 2, 1) is not a unit vector. Its length is:\[\sqrt{0^2+2^2+1^2}=\sqrt{5}\] so divide all the entries of the vector by root 5 and you have a unit vector.
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