Question

differential equations....use the method of variation of parameters to find a particular solution of the given equation y'' - 2y' + y = 3e^(3x) differential equations....use the method of variation of parameters to find a particular solution of the given equation y'' - 2y' + y = 3e^(3x) @Mathematics

Answer 1

i get C1 e^x + c2e^x x + e^(3x).....that sound right to anyone?

Answer 2

That's correct.

Answer 3

woot woot!

Answer 4

1 is a repeat root, so c1.e^x + c2.x.e^x are the homogeneous solutions

Answer 5

only took me an hour to get that lol

Answer 6

i get to take a real class on ODEs next term yay!!

Answer 7

it's kinda interesting...difficult concepts but interesting none the less

Answer 8

there is one that i can almost recall, v=y/x ... but what is that called?

Answer 9

homogeneous equation

Answer 10

james...i wrote the equation wrong

Answer 11

it's y'' - 2y' + y = 4e^(3x)

Answer 12

So yes if y = e^3x, then we have
y'' - 2y' + y = (9-6+1)e^3x = 4e^3x

Answer 13

Ok, so yes indeed
y = c1.e^x + c2.x.e^x + e^3x
is the general solution.

Answer 14

thank....god

Answer 15

i got 4 left...i gotta work on them...u gonna be online so u can double check me by chance?

Answer 16

Probably, yes.

Answer 17

great...thx for your help