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5/49z^3 + 1/35z^3
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\[ \frac{32 z^3}{245} \]
32/245Z^3
the numerator wouldnt be 25+7z?
i have the denominator as 245z^3
no u will have numerator as 32 and denominator as 245Z^3
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\[\frac{5}{49}z^3+\frac{1}{35}z^3\]\[\frac{5\times35}{49\times35}z^3+\frac{1\times49}{35\times49}z^3\]\[\frac{175}{1715}z^3+\frac{49}{1715}z^3\]\[\frac{224}{1715}z^3\]\[\frac{32}{245}z^3\]
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