This is confusing me D:
Solve:
2x=4+sqrt(7x-12) This is confusing me D:
Solve:
2x=4+sqrt(7x-12) @Mathematics

Question

anonymous · Answer

take the 4 to the left side, then square both sides

anonymous · Answer

subtract 4, then square both sides

anonymous · Answer

what lagrange said

anonymous · Answer

of course when i say "take" i mean subtract

anonymous · Answer

that was wrong, it should be 
$$4x^2-16x+16=7x-12$$

lukecrayonz · Answer

Please fully solve. I did that, I got 4x^2-16x+16=7x-12.

anonymous · Answer

ok good

lukecrayonz · Answer

I just need a full explanation, do I factor that now?

anonymous · Answer

then 
$$4x^2-23x+28=0$$ before you can solve

anonymous · Answer

now by some miracle this will factor as 
$$(x-4)(4x-7)=0$$ so 
$$x=4, x=\frac{7}{4}$$

lukecrayonz · Answer

Well in the back of my textbook, it only has the answer of 4, so why do I have 7/4?

anonymous · Answer

but you still have to check both answers to see if they work, because you squared

anonymous · Answer

yes you need to check

lukecrayonz · Answer

Ahh, alright, sorry, I was absent for this lesson :S

anonymous · Answer

when you square both sides you can introduce a solution that was not a solution to the original one. for example if i solve 
$$x-2=4$$ i get 
$$x=6$$ but if i square and solve 
$$(x-2)^2=16$$ i get 
$$x=6,x=-2$$ but only one is a solution to the original equation

lukecrayonz · Answer

I have another question, let me make a new question :)

anonymous · Answer

ok