Question

A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope on the crate? A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope on the crate? @Mathematics

Answer 1

F = M*A so just plug in M*A and solve

Answer 2

incorrect!!!

Answer 3

Yea, I left out gravity...one sec

Answer 4

ok

Answer 5

T = (mg) + (ma) = 67(9.8) + 67(3.5) = 891.1N

Answer 6

correct!!!

Answer 7

when do we normally use this formula? cos i know the normal formula to be f=ma ?

Answer 8

good...I shouldn't have made that first mistake to begin with :)

Answer 9

F=MA is used all the time. For tension, you have to add the downward force PLUS the upward force together to get the *total* force on the rope.

Answer 10

Most of the time when someone misses a physics question like this, it's because they didn't account for all the forces involved. That's why force diagrams are so important.

Answer 11

ok thanks

Answer 12

A 40.0 kg crate is being lowered by means of a rope. Its downward acceleration is 3.80 m/s2. What is the force exerted by the rope on the crate?

Answer 13

Same thing really except that since the acceleration is in the same direction as the force of gravity, you subtract:

T = m(g-a) = 40(9.8 - 3.8) = 240N