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(x+9)^2/3=4
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is that \[(x+9)^{2/3}\] ?
yeah
x+9=(sqrt 4)^3 x+9=8 x=-1
there will be 2 values for x because of the square root
I think you are wrong
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wouldnt it be a cubed root not a square root?
yup
thats what i though but i ended up getting it wrong on my test
hey answer is x = -1
and x = -1 or, -17
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how did you get that?
I think its -8 or 8
how do you get that?
(x+9)^(2/3) = 4 (x+9)^2 = 4^3 (x+9) = 64^(1/2) x+9 = +8 or, -8 x = -1 or. x = -17
how did you get 4^3?
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by cubing both the sides we will get
oh then you just square it?
yes u can do like that too but by that method u will get only one answer x = -1
oh okay thanks
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