Question

ln(x)
----
1/x

Does this expression, if I take the limit for this expression as x --> 0+, does it give an indeterminate form? If so, how?

Answer 1

\[\lim_{x \rightarrow 0^{+}}x*ln(x)=0\]

Answer 2

No I am asking if this gives 0/0, or infinity/infinity

Answer 3

B/c then and only then can I use L'Hop. Rule

Answer 4

yes is goes my friend, if you plug in 0 directtly you will get inifinty/inifinity

Answer 5

How?

Answer 6

ln(0) = - infinity, as x approaches from the right hand side, I understand that part..

Answer 7

1/x, as x approaches 0 from the right hand side outputs infinity, OH OK. So you can put in infinity into the limit expresion? I thought I couldn't do that.

Answer 8

1/0 is infinity, consider the graph:

Answer 9

well you thought wrong lol

Answer 10

you want me wot finish that up for you or can you do it

Answer 11

I can do it, but please PLEASE help me with this new question I am about to post. I am so close to getting the right answer, but I am still getting it "wrong" for some reason.

Answer 12

okay, post it bro

Answer 13

of course the graph i gave you was of 1/x

Answer 14

you are solving
\[\lim_{x\rightarrow 0^+} x\ln(x)\] yes? it is of the form
\[0\times -\infty\]so by changing it to
\[\lim_{x\rightarrow 0^+}\frac{\ln(x)}{\frac{1}{x}}\] you make it into
\[\frac{-\infty}{\infty}\] and so you can use l'hopital

Answer 15

Posted