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For what values of r does the function e^(rx) satisfy the equation y''+5y' -6y=0 (Note: r is a constant.) For what values of r does the function e^(rx) satisfy the equation y''+5y' -6y=0 (Note: r is a constant.) @Mathematics
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solve \[r^2+5r-6=0\]
\[(r+6)(r-1)=0\]
r=-6 r=1
did you just take the derivative of e^rx with respect to r and the second derivative and then plug it in the equation?
\[y=e^{-6x}+e^{1x}\] <- you can check this if you want
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\[ay''+by'+cy=0\] all you have to do to find value of r is solve \[ar^2+br+c=0\]
okay i see thank you
oh and to give a more general answer we say \[y=c_1 e^{-6x}+c_2e^{x}\] c_1,c_2 are constants
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