Question

Solve And Show Steps 8/X^2-16 Subtracted By 1/X-4 = 1

Answer 1

\[8/(x^2-16) - 1/(x-4) = 1\]

\[8/(x^2-16)=8/[(x-4)(x+4)]\]

\[8/[(x-4)(x+4)]-(x+4)/[(x-4)(x+4)]=1\]

\[(8-(x+4))/[(x-4)(x+4)]=1 = (4-x)/[(x-4)(x+4)] \]

multiply both by -1 to convert (4-x) to (x-4) and cancel (x-4) from top and bottom

\[-1 = 1/(x+4)\]

You should be able to solve it for x from there!