Question

A salmon is 2.0 meters away from a 0.55 meter tall waterfall. If the salmon jumps at a 32 degree angle, what is the minimum speed necessary to reach the fall? @Mathematics

Answer 1

for minimum speed take the .55 meter as the max height put it in equation and solve, and also take 2.0 meters as the half horizontal range

I think the formula for horizontal range is \(\Large \frac{u^2*\sin{2\theta}}{g}\) and for max height is \(\Large \frac{u^2*sin^2 \theta}{2g}\)

Answer 2

Hmm, I've never seen those equations in my life haha. This is for a beginning physics course, where there's only 5 standard equations for motion, so do you happen to know how to solve it using those :)?

Answer 3

break it down into the x and y componets

for x component
x-initial = 0 i use x to denote displacement
x-final = 2.0m
v-initial =v-final =? the x component of the velocity, thisis needed
a = 0
t =? useful to find since it is independent of x or y direction

for y component
x-inital =0
x-final = 55.0m
v-initial = ? this is the y component of velocity you need to find
v-final =? not really needed to solve this question
a = -9.8m/s^2
t=?

use proper equations to solve for unknowns then
use trig on v- initial components to solve for v-initial

Answer 4

For both directions, you have 2 unknowns... So how do you solve it?