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Mathematics 14 Online
OpenStudy (anonymous):

Please Solve this question. ∫√Sinx dx

OpenStudy (anonymous):

\[\int \sqrt{\sin{x} }dx\]

OpenStudy (anonymous):

Please post solution also.

OpenStudy (anonymous):

I don't think it has a solution in terms of the elementary functions.

OpenStudy (anonymous):

Is it \(\int\sqrt{\sin{x}}dx\) or \(\int\sin{\sqrt{x}}dx\)?

OpenStudy (anonymous):

Its ∫√sinxdx

OpenStudy (perl):

use the taylor expansion

OpenStudy (anonymous):

I have tried almost everything but If you can solve it by any method then please post the solution,coz I really dont know how to solve this.

OpenStudy (perl):

whats the upper and lower limit

OpenStudy (anonymous):

Its not given.

OpenStudy (anonymous):

solved as an indefinite integral eh?

OpenStudy (anonymous):

What course is this, if you don't mind me asking?

OpenStudy (anonymous):

I have tired as indefinite integral but it gives no result

OpenStudy (anonymous):

so no limits ?

OpenStudy (anonymous):

hmm right if there would be limits I would have solved it

OpenStudy (perl):

from -inf to inf it is 0

OpenStudy (perl):

err

OpenStudy (perl):

nevermind

OpenStudy (perl):

its an elliptic integral

OpenStudy (anonymous):

what class are u taking ?

OpenStudy (anonymous):

so how to solve an elliptic integral? plz tell me

OpenStudy (perl):

you cant you probably have a typo anyway . the question should be integral sin (sqrtx)

OpenStudy (perl):

does it say integral sin ( sqrt x)

OpenStudy (anonymous):

no no its say the integration of whole sinx (under radical)

OpenStudy (perl):

you can copy wolframs answer. sorry thats all i can tell you

OpenStudy (perl):

this is not elementary antiderivative

OpenStudy (perl):

just say its not elementary. and it isnt even easily solved numerically without calculator

OpenStudy (anonymous):

http://www2.wolframalpha.com/input/?i=%E2%88%9ASinx If the input was wrong use this one

OpenStudy (anonymous):

Actually I need solution I have already seen the answer anyway thanks for your response

OpenStudy (anonymous):

Possible derivation: d/dx(sqrt(sin(x))) | Use the chain rule, d/dx(sqrt(sin(x))) = ( dsqrt(u))/( du) ( du)/( dx), where u = sin(x) and ( dsqrt(u))/( du) = 1/(2 sqrt(u)): = | (d/dx(sin(x)))/(2 sqrt(sin(x))) | The derivative of sin(x) is cos(x): = | (cos(x))/(2 sqrt(sin(x)))

OpenStudy (perl):

raw, thats wrong

OpenStudy (perl):

your logic is confusing as heck

OpenStudy (anonymous):

raw no,

OpenStudy (anonymous):

Thanks for the help everyone.

OpenStudy (perl):

raw, all you did was u = sqrt (sin x ) , du = cos x / (2 sqrt (sin x) ) dx .

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