Please Solve this question. ∫√Sinx dx
\[\int \sqrt{\sin{x} }dx\]
Please post solution also.
I don't think it has a solution in terms of the elementary functions.
Is it \(\int\sqrt{\sin{x}}dx\) or \(\int\sin{\sqrt{x}}dx\)?
Its ∫√sinxdx
use the taylor expansion
I have tried almost everything but If you can solve it by any method then please post the solution,coz I really dont know how to solve this.
whats the upper and lower limit
Its not given.
solved as an indefinite integral eh?
What course is this, if you don't mind me asking?
I have tired as indefinite integral but it gives no result
so no limits ?
hmm right if there would be limits I would have solved it
from -inf to inf it is 0
err
nevermind
its an elliptic integral
what class are u taking ?
so how to solve an elliptic integral? plz tell me
you cant you probably have a typo anyway . the question should be integral sin (sqrtx)
does it say integral sin ( sqrt x)
no no its say the integration of whole sinx (under radical)
you can copy wolframs answer. sorry thats all i can tell you
this is not elementary antiderivative
just say its not elementary. and it isnt even easily solved numerically without calculator
http://www2.wolframalpha.com/input/?i=%E2%88%9ASinx If the input was wrong use this one
Actually I need solution I have already seen the answer anyway thanks for your response
Possible derivation: d/dx(sqrt(sin(x))) | Use the chain rule, d/dx(sqrt(sin(x))) = ( dsqrt(u))/( du) ( du)/( dx), where u = sin(x) and ( dsqrt(u))/( du) = 1/(2 sqrt(u)): = | (d/dx(sin(x)))/(2 sqrt(sin(x))) | The derivative of sin(x) is cos(x): = | (cos(x))/(2 sqrt(sin(x)))
raw, thats wrong
your logic is confusing as heck
raw no,
Thanks for the help everyone.
raw, all you did was u = sqrt (sin x ) , du = cos x / (2 sqrt (sin x) ) dx .
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