How would you write the product rule when you have three fcns multipled together?

f(x)g(x)h(x)

[f(x)g(x)h(x)]' = ? How would you write the product rule when you have three fcns multipled together?

f(x)g(x)h(x)

[f(x)g(x)h(x)]' = ? @Mathematics

Question

How would you write the product rule when you have three fcns multipled together?

f(x)g(x)h(x)

[f(x)g(x)h(x)]' = ?  How would you write the product rule when you have three fcns multipled together?

f(x)g(x)h(x)

[f(x)g(x)h(x)]' = ?  @Mathematics

anonymous · Answer

[f(x)g(x)h(x)]'=f'(x)g(x)h(x)+f(x)g'(x)h(x)+f(x)g(x)h'(x)

anonymous · Answer

How do you know?

anonymous · Answer

It is a standard formula. just always take the derivative with respect to one variable, and keep the rest constant. do this for all the variables and you got the formula

precal · Answer

Try it with $$30x ^{2}$$  (use the power rule)
and compare it to (2x)(3x)(5x)  Use the rule given above
since these two functions are equivalent then their derivatives should also, be equal.